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Python Tuples Tutorial with Examples

  1. Python Tuples
  2. List vs Tuple
  3. Access the elements of Tuples
  4. Update Tuples
  5. Operators for Tuples
  6. Functions for Tuples
  7. Methods

1. Python Tuples

In Python, Tuples is a sequence of values containing many elements, which is similar to List. Unlike List, Tuples is an immutable data type, all updates on the Tuple create a new entity on the memory.
In order to write a Tuple, you need to put the elements into parentheses ( ) and separated by comma. These elements of the list are indexed with the starting index 0.
tupleExample.py
fruitTuple = ("apple", "apricot", "banana","coconut", "lemen")
otherTuple = (100, "one", "two", 3)
print ("Fruit Tuple:")
print (fruitTuple)
print (" --------------------------- ")
print ("Other Tuple:")
print (otherTuple)
Output:
Fruit Tuple:
('apple', 'apricot', 'banana', 'coconut', 'lemen')
 ---------------------------
Other List:
(100, 'one', 'two', 3)

2. List vs Tuple

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List and Tuple are a sequence of elements. There are some following differences between them:
  • Writing a list, you need to use square brackets [] while writing a Tuple, you use parentheses ( ).
# This is a Tuple.
aTuple = ("apple", "apricot", "banana")

# This is a List.
aList =  ["apple", "apricot", "banana"]
  • List is a mutable data type, you can use the append() method to add the element to List, or use the remove() method to remove elements from List without creating another "List" entity in memory.
listMemoryTest.py
list1 =  [1990, 1991, 1992] 
print ("list1: ", list1)

# Address of list1 in the memory.
list1Address = hex ( id(list1) ) 
print ("Address of list1: ", list1Address ) 
print ("\n")
print ("Append element 2001 to list1")

# Append a element to list1.
list1.append(2001) 
print ("list1 (After append): ", list1)

# Address of list1 in the memory.
list1Address = hex ( id(list1) ) 
print ("Address of list1 (After append): ", list1Address )
  • Tuple is an immutable object, it does not have the methods append (), remove (),... like list. You may think that some methods, or operators are used to update Tuple but the fact that it is based on the original Tuple to create a new Tuple.
tupleMemoryTest.py
tuple1 =  (1990, 1991, 1992)

# Address of tuple1 in the memory.
tuple1Address = hex ( id(tuple1) ) 
print ("Address of tuple1: ", tuple1Address )

# Concatenate a tuple to tuple1.
tuple1 = tuple1 + (2001, 2002)

# Address of tuple1 in the memory.
tuple1Address = hex ( id(tuple1) )  
print ("Address of tuple1 (After concat): ", tuple1Address )
Output:
Address of tuple1: 0x9096751d80
Address of tuple1 (After concat): 0x9096778f10

3. Access the elements of Tuples

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Access the elements
Use the 'for' loop to access the elements of Tuple:
elementAccessExample.py
fruits = ("apple", "apricot", "banana", "coconut", "lemen", "plum", "pear")

for fruit in fruits :
    print ("Fruit: ", fruit)
Output:
Fruit: apple
Fruit: apricot
Fruit: banana
Fruit: coconut
Fruit: lemen
Fruit: plum
Fruit: pear
Access via index:
You can also access the elements of Tuple via index. The elements of Tuple are indexed from left to right, starting at 0.
indexAccessExample.py
fruits = ("apple", "apricot", "banana", "coconut", "lemen", "plum", "pear") 
print ( fruits )

# Element count.
print ("Element count: ", len(fruits) ) 

for i in range (0, len(fruits) ) : 
    print ("Element at ", i, "= ", fruits[i] )
    
# A sub Tuple of elements with index from 1 to 4 (1, 2, 3)
subTuple = fruits[1: 4]    
# ('apricot', 'banana', 'coconut')
print ("Sub Tuple [1:4] ", subTuple )
Output:
('apple', 'apricot', 'banana', 'coconut', 'lemen', 'plum', 'pear')
Element count: 7
Element at 0 = apple
Element at 1 = apricot
Element at 2 = banana
Element at 3 = coconut
Element at 4 = lemen
Element at 5 = plum
Element at 6 = pear
Sub Tuple [1:4]  ('apricot', 'banana', 'coconut')
You can also access the elements of Tuple via negative index, the elements are indexed from right to left with the values -1, -2,...
indexAccessExample2.py
fruits = ("apple", "apricot", "banana", "coconut", "lemen", "plum", "pear")
print ( fruits )
print ("Element count: ", len(fruits) )

print ("fruits[-1]: ", fruits[-1])
print ("fruits[-2]: ", fruits[-2]) 
subTuple1 = fruits[-4: ]

print ("\n")
print ("Sub Tuple fruits[-4: ] ")
print (subTuple1) 
subTuple2  = fruits[-4:-2]
print ("\n")
print ("Sub Tuple fruits[-4:-2] ")
print (subTuple2)
Output:
('apple', 'apricot', 'banana', 'coconut', 'lemen', 'plum', 'pear')
Element count: 7
fruitList[-1]:  pear
fruitList[-2]:  plum  
 
Sub Tuple fruits[-4: ]  
('coconut', 'lemen', 'plum', 'pear')

Sub Tuple fruits[-4:-2]  
('coconut', 'lemen')

4. Update Tuples

Note that Tuple is immutable, so it only has methods or operators to access, or create a new Tuple from the original Tuple.
updateTupleExample.py
tuple1 = (1990, 1991, 1992) 
print ("tuple1: ", tuple1)  
print ("Concat (2001, 2002) to tuple1") 
 
tuple2 = tuple1 + (2001, 2002)  
print ("tuple2: ", tuple2)

# A sub Tuple, containing elements from index 1 to 4 (1,2,3)
tuple3 = tuple2[1:4] 
print ("tuple2[1:4]: ", tuple3)

# A sub Tuple, containing elements from index 1 to the end.
tuple4 = tuple2[1: ] 
print ("tuple2[1: ]: ", tuple4)
Output:
tuple1: (1990, 1991, 1992)
Concat (2001, 2002) to tuple1
tuple2: (1990, 1991, 1992, 2001, 2002)
tuple2[1:4]: (1991, 1992, 2001)
tuple2[1: ]: (1991, 1992, 2001, 2002)

5. Operators for Tuples

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The same as String, Tuple has 3 operators including +, * , in.
Operator
Description
Example
+
The operator is used to concatenate 2 Tuples to create a new Tuple
(1, 2, 3) + ("One","Two")
--> (1, 2, 3, "One", "Two")
*
The operator is used to concatenate multiple copies of the same Tuple. And create a new Tuple
(1, 2) * 3
--> (1, 2, 1, 2, 1, 2)
in
Check whether an element is in a Tuple, which returns True or False.
"Abc" in ("One", "Abc")
--> True
tupleOperatorsExample.py
tuple1 = (1, 2, 3)
tuple2 = ("One", "Two")
print ("tuple1: ", tuple1)
print ("tuple2: ", tuple2)
print ("\n")

tuple12 = tuple1 + tuple2
print ("tuple1 + tuple2: ", tuple12)
tuple2x3 = tuple2 * 3
print ("tuple2 * 3: ", tuple2x3)
hasThree = "Three" in tuple2
print ("'Three' in tuple2? ", hasThree)
Output:
tuple1: (1, 2, 3)
tuple2: ('One', 'Two')

tuple1 + tuple2: (1, 2, 3, 'One', 'Two')
list2 * 3: ('One', 'Two', 'One', 'Two', 'One', 'Two')
'Three' in tuple2? False

6. Functions for Tuples

Function
Description
cmp(list1, list2)
Compares elements of both Tuples. This function was removed from Python3.
len(list)
Gives the total length of the Tuple.
max(list)
Returns item from the Tuple with max value.
min(list)
Returns item from the Tuple with min value.
tuple(seq)
Converts a List into Tuple.
tupleFunctionsExample.py
tuple1 = (1991, 1994, 1992)
tuple2 = (1991, 1994, 2000, 1992)
print ("tuple1: ", tuple1)
print ("tuple2: ", tuple2)

# Return element count.
print ("len(tuple1): ", len(tuple1) )
print ("len(tuple2): ", len(tuple2) )

# Maxinum value in the Tuple.
maxValue = max(tuple1)
print ("Max value of tuple1: ", maxValue)

# Minimum value in the Tuple.
minValue = min(tuple1)
print ("Min value of tuple1: ", minValue)

# (all)
# List
list3 = [2001, 2005, 2012]
print ("list3: ", list3)

# Convert a List to a tuple.
tuple3 = tuple (list3)
print ("tuple3: ", tuple3)
Output:
tuple1: (1991, 1994, 1992)
tuple2: (1991, 1994, 2000, 1992)
len(tuple1): 3
len(tuple2): 4
Max value of tuple1: 1994
Min value of tuple1: 1991
list3: [2001, 2005, 2012]
tuple3: (2001, 2005, 2012)
See more:
  • Comparing and Sorting in Python

7. Methods

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Method
Description
tuple.count(obj)
Returns count of how many times obj occurs in Tuple
tuple.index(obj, [start, [stop]])
Returns the lowest index in Tuple that obj appears. Raises ValueError if the value not found.

If there are parameters start, stop, just search from start to stop index (And not included stop).
Example:
tupleMethodsExample.py
years =  ( 1990 ,  1991 ,  1993 ,  1991 ,  1993 ,  1993 ,  1993 )
print ("Years: ", years)
print ("\n") 

# return number of occurrences of 1993
print ("years.count(1993): ",years.count(1993) ) 

# Find the index that appears 1993
print ("years.index(1993): ", years.index(1993) )

# Find the index that appears 1993, from index 3
print ("years.index(1993, 3): ", years.index(1993, 3) )

# Find the index that appears 1993, from index 4 to 5 (Not included 6)
print ("years.index(1993, 4, 6): ", years.index(1993, 4, 6) )
Output:
Years: (1990, 1991, 1993, 1991, 1993, 1993, 1993)

years.count(1993): 4
years.index(1993): 2
years.index(1993, 3): 4
years.index(1993, 4, 6): 4
See more:
  • Comparing and Sorting in Python
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